Question

Questão de logaritmos na foto, me ajude!

Answer 1

$h(x) = log(10^1^,^3^5\ \cdot\ \sqrt[4]{2x} )$

$h(5) = log(10^1^,^3^5\ \cdot\ \sqrt[4]{2*5} )$

$h(5) = log(10^1^,^3^5\ \cdot\ \sqrt[4]{10} )\\\\ \sqrt[4]{10} = 10^\frac{1}{4} = 10^0^,^2^5\\\\\ h(5) = log(10^1^,^3^5\ \cdot\ 10^0^,^2^5 )$

$h(5) = log(10^1^,^3^5\ \cdot\ 10^0^,^2^5 ) \\\\\ 10^1^,^3^5\ \cdot\ 10^0^,^2^5 = 10^1^,^6\\\\\ h(5) = log\ 10^1^,^6\\\\\ log\ 10^1^,^6 = x\\\\\ 10^x = 10^1^,^6\\\\ x = 1,6$

$\boxed{h(5) = 1,6\ m}$