Question

Questão de funções.

Answer 1

Caroline,
Ajudo com a primeira..

             $f(x) = \frac{x^2-4}{x-1}$

                           $f(0) = \frac{0^2-4}{0-1} = \frac{-4}{-1} =4 \\ \\ f(x-2)= \frac{(x-2)^2-4}{(x-2)-1} = \frac{x^2-4x+4-4}{x-2-1} = \frac{x^2-4x}{x-3} \\ \\ f( \frac{1}{2})= \frac{( \frac{1}{2})^2-4 }{ \frac{1}{2} -1} = \frac{ \frac{1}{4} -4}{ \frac{1}{2}-1 } = \frac{ \frac{1}{4}- \frac{16}{4} }{ \frac{1}{2}- \frac{2}{2} } = \frac{- \frac{15}{4} }{- \frac{1}{2} } = \frac{15.2}{4.1} = \frac{15}{2}$