Question

Questao de dizima periódica

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Answer 1

$\frac{13 - 1}{90} + \frac{27}{99} \\ \frac{12}{90} + \frac{27}{99} \\ \frac{4}{30} + \frac{9}{33} \\ \frac{2}{15} + \frac{3}{11} \\ \frac{22 + 45}{165} \\ \frac{67}{165}$