Question

Questão 9 PFV ME AJUDEM PFV PEÇO MUITO OBRIGADO PRA QUEM ME RESPONDER FIQUE COM DEUS

Answer 1

$a)\frac{a}{b} = \frac{-3}{-1} = 3$

$b)\frac{a + b}{c} = \frac{-3 - 1}{4} = \frac{-4}{4} = -1$

$c)b - d = -1 - (-10) = -1 + 10 = 9$

$d)(d + b)^2 = (-10 + (-1))^2 = (-10 - 1)^2 = (-11)^2 = 121$

$e) b^3 * c^2 = (-3)^3 * (4)^2 = -27 * 16 = -432$

$f) \frac{a*d}{c - b} = \frac{(-3)*(-10)}{4 - (-1)} = \frac{30}{4 + 1} = \frac{30}{5} = 6$

$g) a * b * c = (-3) * (-1) * (4) = 12$

$h) a + b - c - d = (-3) + (-1) - (4) - (-10) = -3 - 1 - 4 + 10 = 2$

Answer 2

Oie, Td Bom?!

>>> Substitua: a = - 3, b = - 1, c = 4 e d = - 10

a)

$\frac{a}{b} = 3$

$\frac{ - 3}{ - 1} = 3$

b)

$\frac{a + b}{c}$

$\frac{( - 3) + ( - 1)}{4}$

$\frac{ - 3 - 1}{4}$

$\frac{ - 4}{4}$

$- 1$

c)

$b - d$

$( - 1) - ( - 10)$

$- 1 + 10$

$9$

d)

$(d + b) {}^{2}$

$(( - 10) + ( - 1)) {}^{2}$

$( - 1 0 - 1) {}^{2}$

$( - 11) {}^{2}$

$11 {}^{2}$

$11 \times 11$

$121$

e)

$b {}^{3} \times c {}^{2}$

$( - 1) {}^{3} \times 4 {}^{2}$

$- 1 \times 16$

$- 16$

f)

$\frac{a \times d}{c \times b}$

$\frac{( - 3) \times ( - 10)}{4 \times ( - 1)}$

$- \frac{3 \times 10}{4 \times 1}$

$- \frac{3 \times 10}{4}$

$- \frac{3 \times 10 \div 2}{4 \div 2}$

$- \frac{3 \times 5}{2}$

$- \frac{15}{2}$

g)

$a \times b \times c$

$( - 3) \times ( - 1) \times 4$

$3 \times 1 \times 4$

$3 \times 4$

$12$

h)

$a + b - c - d$

$( - 3) + ( - 1) - 4 - ( - 10)$

$- 3 - 1 - 4 + 10$

$- 8 + 10$

$2$

Att. Makaveli1996