Matemática, perguntado por izamoura347, 6 meses atrás

Questão 1 - Calcule as adições com números inteiros,
a)(-4) + (-3) =
b)(-7) + (-8) =
c) (-4) + (-6)=
d)(- 9) + (-3) =
e)(-8) + (- 9) =
f) (-6) + (-5)
g)(-6) + (-15) =
h)(-17) + (-3) =
i) (-5) + (-1) =
1) (-6) + (- 10) =
k) (-15) + (-14) =
1) (- 13) + (-7)=
m)(-55)+(-8)
(-55) + (-8) =
n)(-3) + (-8)=
0)(-1) + (-1)​


izamoura347: me ajudem

Soluções para a tarefa

Respondido por tatyanerietmann
0

Ok tá bom também?

a)

\begin{gathered}( - 4) + ( - 3) \\ + 7\end{gathered}

(−4)+(−3)

+7

b)

\begin{gathered}( - 7) + ( - 8) = \\ + 15\end{gathered}

(−7)+(−8)=

+15

c)

\begin{gathered}( - 4) + ( - 6) = \\ + 10\end{gathered}

(−4)+(−6)=

+10

d)

\begin{gathered}( - 9) + ( - 3) \\ + 12\end{gathered}

(−9)+(−3)

+12

e)

\begin{gathered}( - 8) + ( - 9) = \\ 17\end{gathered}

(−8)+(−9)=

17

f)

\begin{gathered}( - 6) + ( - 5) = \\ + 11\end{gathered}

(−6)+(−5)=

+11

g)

\begin{gathered}( - 6) + ( - 15) = \\ + 21\end{gathered}

(−6)+(−15)=

+21

h)

\begin{gathered}( - 17) + ( - 3) = \\ + 20\end{gathered}

(−17)+(−3)=

+20

i)

\begin{gathered}( - 5) + ( - 1) = \\ + 6\end{gathered}

(−5)+(−1)=

+6

j)

\begin{gathered}( - 6) + ( - 10) = \\ + 16\end{gathered}

(−6)+(−10)=

+16

k)

\begin{gathered}( - 15) + ( - 14) = \\ + 29\end{gathered}

(−15)+(−14)=

+29

l)

\begin{gathered}( - 55) + ( - 8) = \\ 63\end{gathered}

(−55)+(−8)=

63

m)

\begin{gathered}( - 3) + ( - 8) = \\ + 11\end{gathered}

(−3)+(−8)=

+11

n)

\begin{gathered}( - 1) + ( - 1) = \\ + 2\end{gathered}

(−1)+(−1)=

+2

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