Question

Quem Pode mim ajudar ?

Answer 1

$Ola' \\ \\ 3)~Resolver \\ \\ a)~ \frac{ (5^{4}. 4^{6}) }{ 6^{9} } = \frac{ 5^{4}.2^{12} }{ 2^{9}. 3^{9} } = \frac{ 5^{4} .2^{3} }{ 3^{9} }= \frac{625.(8)}{19683} = 0,2540..... \\ \\ b)~ \frac{ b^{(2x+5x+7-4x)} }{ b^{(-9x)} } = \frac{ b^{3x+9} }{ b^{(-9x)} } = b^{3x}. b^{9} . b^{9x}= b^{12x} . b^{9}= b^{3(4x+3)} \\ \\ \\ \mathbb{iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii} \\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Bons ~estudos!!$