Que taxa mensal faz com R$2.150,00 produzam R$700,00 de juros em 7 meses?
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Boa noite!
A juros simples:
A juros compostos:
![<br />M=C+J=2150+700=2850\\<br />M=C(1+i)^n\\<br />2850=2150(1+i)^7\\<br />(1+i)^7=\frac{2850}{2150}\\<br />1+i=\sqrt[7]{\frac{2850}{2150}}\\<br />i=\sqrt[7]{\frac{2850}{2150}}-1\\<br />i\approx{4,11\%\text{ a.m.}}<br />](https://tex.z-dn.net/?f=%3Cbr+%2F%3EM%3DC%2BJ%3D2150%2B700%3D2850%5C%5C%3Cbr+%2F%3EM%3DC%281%2Bi%29%5En%5C%5C%3Cbr+%2F%3E2850%3D2150%281%2Bi%29%5E7%5C%5C%3Cbr+%2F%3E%281%2Bi%29%5E7%3D%5Cfrac%7B2850%7D%7B2150%7D%5C%5C%3Cbr+%2F%3E1%2Bi%3D%5Csqrt%5B7%5D%7B%5Cfrac%7B2850%7D%7B2150%7D%7D%5C%5C%3Cbr+%2F%3Ei%3D%5Csqrt%5B7%5D%7B%5Cfrac%7B2850%7D%7B2150%7D%7D-1%5C%5C%3Cbr+%2F%3Ei%5Capprox%7B4%2C11%5C%25%5Ctext%7B+a.m.%7D%7D%3Cbr+%2F%3E "<br />M=C+J=2150+700=2850\\<br />M=C(1+i)^n\\<br />2850=2150(1+i)^7\\<br />(1+i)^7=\frac{2850}{2150}\\<br />1+i=\sqrt[7]{\frac{2850}{2150}}\\<br />i=\sqrt[7]{\frac{2850}{2150}}-1\\<br />i\approx{4,11\%\text{ a.m.}}<br />")
Espero ter ajudado!
A juros simples:
A juros compostos:
Espero ter ajudado!
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