Question

Quantos termos tem a pg (1/49, 1/7,...16807)

Answer 1

Resposta:

$a1 = \frac{1}{49} \\ q = \frac{a2}{a1} \\ q = \frac{(1 \div 7)}{(1 \div 49)} \\ q = 7 \\ an = 16807\\ an = a1.q ^{(n - 1)} \\ 16807 = \frac{1}{49} .7 ^{(n - 1)} \\ 823543 = 7 ^{(n - 1)} \\ 7 ^{7} = 7 ^{(n - 1)} \\ corta \: 7 \: a \: base \: 7 \\ 7 = n - 1 \\ n = 8termos$