Question

Quantos termos a sequência. (5, 9, 13,…,37) possui?​

Answer 1

Resposta:

an=a1+(n−1)r

37=5+(n-1)437=5+(n−1)4

37-5=4n-437−5=4n−4

32=4n-432=4n−4

32+4=4n32+4=4n

36=4n36=4n

n=36/4n=36/4

n=9n=9

Answer 2

n=an-a1/r + 1

n=37-5/4 + 1

n=32/4 + 1

n= 8 + 1

n= 9