Question

quantos são os múltiplos de 4 compreendido entre 6 e 101

Answer 1

$P.A~(8,12,16,...,100)$

$a_{1}=8\\a_{2}=12\\\\q=a_{2}-a_{1}=12-8=4$

$a_{n}=a_{1}+(n-1)r\\100=8+(n-1)4$
$100 - 8 = (n - 1)4\\92=(n - 1)4\\92/4=(n - 1)\\n - 1= 23\\n = 23 + 1\\\\\boxed{\boxed{n=24}}$