Quantos mols estão presentes em?
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a) Calculo da massa molar :
H₂O = 1* 2 + 16 => 18 g/mol
1 mol H₂O ------------ 18 g
n mol-------------------- 90 g
n = 90 * 1 / 18
n = 90 / 18
n = 5,0 mols
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b) C₃H₄O₃ = 12 * 3 + 1 * 4 + 16 * 3 => 88 g/mol
1 mol C₃H₄O₃----------------------- 88 g
n mol ---------------------------------532g
n = 532 * 1 / 88
n = 532 / 88
n = 6,04 mols
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c) CaCO₃ = 40 + 12 + 16 * 3 => 100 g/mol
1 mol CaCO₃-------------------- 100g
n mol------------------------------ 100 g
n = 100 * 1 / 100
n = 100 / 100
n = 1,0 mol
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d) CH₃ = 12 + 1 * 3 => 15 g/mol
1 mol CH₃ ---------------- 15 g
n mol -----------------------135 g
n = 135 * 1 / 15
n = 135 / 15
n = 9,0 mols
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a) Calculo da massa molar :
H₂O = 1* 2 + 16 => 18 g/mol
1 mol H₂O ------------ 18 g
n mol-------------------- 90 g
n = 90 * 1 / 18
n = 90 / 18
n = 5,0 mols
_________________________________________
b) C₃H₄O₃ = 12 * 3 + 1 * 4 + 16 * 3 => 88 g/mol
1 mol C₃H₄O₃----------------------- 88 g
n mol ---------------------------------532g
n = 532 * 1 / 88
n = 532 / 88
n = 6,04 mols
__________________________________________________
c) CaCO₃ = 40 + 12 + 16 * 3 => 100 g/mol
1 mol CaCO₃-------------------- 100g
n mol------------------------------ 100 g
n = 100 * 1 / 100
n = 100 / 100
n = 1,0 mol
_____________________________________________________
d) CH₃ = 12 + 1 * 3 => 15 g/mol
1 mol CH₃ ---------------- 15 g
n mol -----------------------135 g
n = 135 * 1 / 15
n = 135 / 15
n = 9,0 mols
________________________________________________________
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