Question

Quantos mols de Hcl são necessários para produzir 12 mols de cloreto de alumínio?​

Answer 1

$\large\boxed{\begin{array}{l}\sf 2AlCl_3+3H_2SO_4\longrightarrow Al_2(SO_4)_3+6HCl\\\underline{\rm montagem~da~regra~de~tr\hat es\!:}\\\\\sf 6~mol~de~HCl\longrightarrow 2~mol~AlCl_3\\\sf x\longrightarrow 12~mols~de~AlCl_3\\\sf 2x=72\\\sf x=\dfrac{72}{2}\\\\\sf x=36~mols~HCl\end{array}}$