Question

quantos mols correspondem a 189 g de ácido nitrico. (H=1, 0=16, N=14)

Answer 1

Massa molar:

HNO3 = 1 + 14 + 16 x 3 => 63 g/mol 

1 mol HNO3 ------------- 63 g
x mol HNO3 ------------- 189 g

x = 189 / 63

x = 3,0 mols