Question

quantos litros de oxigenio molecular são necessaries para a combustao completa de 75 g de carbono em CNTP​

Answer 1

$\boxed{\begin{array}{l}\sf12~g\longrightarrow 22,4~L\\\sf 75~g\longrightarrow x\\\sf 12x=22,4\cdot75\\\sf 12x=1680\\\sf x=\dfrac{1680}{12}\\\\\sf x=140~L\end{array}}$