Question

quanto mede a diagonal de um paralelpipedo reto retangular no qual as  sao 10cm 6cm 8cm?

 

Answer 1

a = 10
b = 6
c = 8
d = \/(a²+b²+c²)
d = \/(10²+6²+8²)
d = \/(100+36+64)
d = \/(100+100)
d = \/(200)
d = \/(2x100)
d = 10\/2 cm
ou
d ~ 10 x 1,41
d ~ 14,1 cm