Question

Quanto mede a diagonal de um paralelepipedo reto retangular no qual as dimensoes sao 10 cm, 6 cm e 8 cm ?

Answer 1

Diagonal da base:

$(d_B)^2=10^2+6^2=136$

Diagonal do paralelepípedo:

$(d_P}^2=136+64 = 200 \\ \\ d_P=\sqrt{200}=10\sqrt2$

Answer 2

    Dbase = a^2 + b^2

    (Dbase)^2= 10^2 + 8^2 = 100+ 64 = 164

    (Dparap)^2 = 164 + 6^2 ==> 164+36

    (Dparap)^2 = 200  ==> V200

      (Dparap) = 10V2