Question

Quanto é 4 elevado a log de 2 que da 9??? ( 4^log2 9)

Answer 1

$4^{log_{2}9} \\\\ (2^{2})^{log_{2}9} \\\\ 2^{2log_{2}9} \\\\ 2^{log_{2}9^{2}} \\\\ \text{pela pripriedade} \rightarrow \boxed{x^{log_{x}y} = y} \\\\ 2^{log_{2}81} = \boxed{\boxed{81}}$

Answer 2

Propriedade dos logs

$a^(^l^o^g^a^b^) = b$

Quando temos a base do expoente igual a base do logaritmo, a resposta é o logaritmando.

$4^(^l^o^g^2^9^)\\\\ 2^2^(^l^o^g^2^9^)\\\\ 2^(^2^l^o^g^2^9^)\\\\ 2^(^l^o^g^2^9^2^)\\\\ 2^(^l^o^g^2^8^1^)\\\\ \boxed{81}$