Question

quanto é 3x²- 4 =4x² + 2x - 3?
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Answer 1

$3x^2-4=4x^2-2x-3\\\\x^2-2x+1=0$

a=1

b=-2

c=1

Resolvendo por soma e produto:

$\frac{-b}{a}=x'+x'' \\\\2 =x'}+x'' \\\\ \frac{c}{a}=x'*x''\\\\ 1=x'*x''\\\\ Logo: x'=x''=1$

Resolvendo por Bhaskara:

$Delta=b^2-4ac\\\\Delta = (-2)^2-4 = 0\\\\Logo: x'=x''=\frac{-b}{2a} = \frac{-(-2)}{2} = \frac{2}{2}= 1$

Resolvendo por completamento de quadrado:

$x^2-2x+1=0\\\\x^2-2x=-1\\\\x^2-2x+1^2=-1+1^2\\\\(x-1)^2=0\\\\\sqrt{(x-1^2)}=\sqrt{0} \\\\(x'-1)= 0\\\\(x''-1)=0\\\\x'=x''=1$