Question

quanto é
(3x-½).(x²+4)
PLEASEEEE
​

Answer 1

Explicação passo-a-passo:

$\sf (3x-\frac{1}{2})\cdot(x^2+4)$

$\sf =3x^3+12x-\dfrac{x^2}{2}-2$

$\sf =\red{3x^3-\dfrac{x^2}{2}+12x-2}$

Answer 2

Oie, Td Bom?!

$= (3x - \frac{1}{2} ) \: . \: (x {}^{2} + 4)$

$= 3x \: . \: (x {}^{2} + 4) - \frac{1}{2} \: . \: (x {}^{2} + 4)$

$= 3x {}^{3} + 12x - \frac{1}{2} x {}^{2} - 2$

Att. Makaveli1996