Matemática, perguntado por ramon161105, 1 ano atrás

Qual seria a resposta de

A) (y + 4) . 7

B) c² + 8 sobre 10 - 5

C) (3t - 2) ² + 9

Soluções para a tarefa

Respondido por GeBEfte
2

a)\\\\\\(y+4)~.~7~=\\\\\\Aplicando~a~propriedade~distributiva~da~multiplicacao\\\\\\=~7~.~y~+~4~.~7\\\\\\=~\boxed{7y~+~28}\\\\\\\\

b)\\\\\\c^2~+~\frac{8}{10}-5~=\\\\\\=~c^2~+~\frac{1~.~8~-~10~.~5}{10}\\\\\\=~c^2~+~\frac{8~-~50}{10}\\\\\\=~c^2~-~\frac{42}{10}\\\\\\=~\boxed{c^2~-~\frac{21}{5}}~~~~ou~~~~\boxed{c^2~-~4,2}

c)\\\\\\(3t-2)^2~+~9~=\\\\\\=~(3t-2)~.~(3t-2)~+~9\\\\\\Aplicando~a~propriedade~distributiva~da~multiplicacao\\\\\\=~3t~.~3t~+~3t~.~(-2)~+~(-2)~.~3t~+~(-2)~.~(-2)~~+~9\\\\\\=~9t^2~-~6t~-~6t~+~4~+~9\\\\\\=~\boxed{9t^2\,-\,12t~+~13}

Perguntas interessantes