Question

qual sera a soma dos termos da pg 2/7, 2, 14.... considerando n=8

Answer 1

a1 = 2/7

a2 = 2

a3 = 14

n = 8

S8 = a1 ( qⁿ - 1 )/ ( q - 1)

S8 = 2/7 ( 7⁸ - 1 )/ ( 7 - 1 )

S8 = 2/7 ( 5764801 - 1 )/ 6

S8 = 2/7 (5764800 )/6

s8 = 2/7 (960800 )

( 960800 * 2)/7

s8 = 1921600/7 =274514,3 ******