Question

qual e valor do x1 e do x2 na seguinte equacao: x²+18x+80=0

Answer 1

x^2 + 18x + 80 = 0

Aplicando Bháskara:

Delta = b^2 - 4 * a * c

Delta = 18^2 - 4 * 1 * 80

Delta = 324 - 320

Delta = 4

x = -b +- raiz de delta / 2*a

x = - (+18) +- raiz de 4 / 2*1

x = -18 +- 2 / 2

x1 = -18 + 2 / 2

x1 = -16/2

x1 = -8

x2 = -18 - 2 / 2

x2 = -20 / 2

x2 = -10