Question

qual é o valor na escala fahrenheit da temperatura de 258 kelvin​

Answer 1

$\frac{TF-32}{9}$=$\frac{TK-273}{5}$

$\frac{TF-32}{9}$=$\frac{258-273}{5}$

$\frac{TF-32}{9}$=$\frac{-15}{5}$

5·(TF-32)=9·(-15)

5TF-160= (-135)

5TF= (-135) + 160

5TF= -25

TF=$\frac{-25}{5}$

TF= -5°F