Question

Qual é o valor de y, para 5^2x + 4 = $\sqrt{125}$

Answer 1

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$\sf{5^{2x+4}=\sqrt{125}}\\\sf{5^{2x+4}=\sqrt{5^3}}\\\sf{5^{2x+4}=5^{\frac{3}{2}}}\\\sf{2x+4=\dfrac{3}{2}}\\\sf{4x+8=3}\\\sf{4x=3-8}\\\sf{4x=-5}\\\huge\boxed{\boxed{\boxed{\boxed{\sf{x=-\dfrac{5}{4}}}}}}$