Question

qual é o numero real X expresso por (√ 6.√ 4 + √ 12.√ 32) / 2?

Answer 1

$\sqrt{4}=\sqrt{2^{2}}=2^{(2/2)}=2\\\sqrt{12}=\sqrt{4.3}=\sqrt{4}.\sqrt{3}=2.\sqrt{3}=2\sqrt{3}\\\sqrt{32}=\sqrt{16.2}=\sqrt{16}.\sqrt{2}=4.\sqrt{2}=4\sqrt{2}$

$(\sqrt{6}.\sqrt{4}+\sqrt{12}.\sqrt{32})/2=(\sqrt{6}.2+2\sqrt{3}.4\sqrt{2})/2\\(\sqrt{6}.\sqrt{4}+\sqrt{12}.\sqrt{32})/2=(2\sqrt{6}+8\sqrt{3.2})/2\\(\sqrt{6}.\sqrt{4}+\sqrt{12}.\sqrt{32})/2=(2\sqrt{6}+8\sqrt{6})/2\\(\sqrt{6}.\sqrt{4}+\sqrt{12}.\sqrt{32})/2=10\sqrt{6}/2\\(\sqrt{6}.\sqrt{4}+\sqrt{12}.\sqrt{32})/2=5\sqrt{6}$