Question

qual é a massa molar de:
CsOH

FrO

H2O

KBr

NaCl

Al(OH)3

Ca2O

Sr2Cl

NH4OH

LiCl

H2SO4

HNO3

HCl

KI

H3PO4

Ba2Br

Ba2Cl

Ba(OH)2

FrCl

Ra2Cl

Ca(OH)2

RbCl

RbOH​

Answer 1

Resposta:

CsOH

133+ 16+ 1= 150 g

Explicação:

Fr2O

223×2+ 16=

446+ 16=. 462 g

H2O

2+ 16= 18 g

KBr

39+80= 119 g

NaCl

23+ 35,5= 58,5 g

Al(OH)3

27+ 16×3+ 1×3=

27+48+3= 78 g

CaO

40+16= 56 g

SrCl2

87+ 35,5 ×2=

87+ 71 = 158 g

NH4OH

14+4+16+1= 35 g

LiCl

7+35,5= 42,5 g

H2SO4

2+32+ 64= 98 g

HNO3

1+32+48= 81 g

HCl

1+ 35,5= 36,5 g

KI

39+ 127=. 166 g

H3PO4

3+31+64= 98 g

BaBr2

137+ 80×2=

137+ 160=. 297 g

BaCl2

137+ 35,5 ×2=

137+ 71=. 208. g

Ba(OH)2

137+ 16×2+ 2=

137+32+2=.171. g

FrCl

223+ 35,5= 258,5 g

RaCl2

226+ 35,5 ×2=

226+ 71=. 297 g

Ca(OH)2

40+16×2+2=

40+32+2= 74 g

RbCl

85,5 + 35,5=. 121. g

RbOH

85,5 + 16+1= 102,5 g