Question

Qual é a derivada e elavado a lnx + 1

Answer 1

Derivada de função exponencial

$\boxed{\frac{d}{dx}({e}^{u})={e}^{u}.\frac{du}{dx}}$

$\frac{d}{dx}({e}^{ln(x)} +1)={e}^{ln(x)}. \frac{d}{dx}(ln(x))$

$\boxed{\frac{d}{dx}{e}^{ln(x)}+1=x.\frac{1}{x}=1}$