Question

qual e a area da figura a seguir ?

 

 

Answer 1

Diagonal do quadrado = $l \sqrt{2}$

$3 \sqrt{3} =l \sqrt{2}$

$l=\frac{3\sqrt{3}}{\sqrt{2}}=\frac{3\sqrt{6}}{2}$

$Area=l^2+ \frac{l^2}{2} =(\frac{3\sqrt{6}}{2})^2+\frac{(\frac{3\sqrt{6}}{2})^2}{2}$

$=\frac{9.6}{4}+\frac{\frac{9.6}{4}}{2}=\frac{9.6}{4}+\frac{9.6}{8}$

$=\frac{54}{4}+\frac{27}{4}=\frac{81}{4}$

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