Question

Qual de ser o valor racional de x para que se tenha 2/3x+5.(2x-3)=3.(4x-1)/2+11?

Answer 1

2/3x + 5 • (2x-3) = 3 • (4x-1)/2 + 11 

2x/3 + 10x – 15 = (12x – 3)/2 + 11 

2x/3 + 10x = (12x – 3)/2 + 26 

mcm = 6 

4x + 60x = 36x – 9 + 156 

64x – 36x = 147 

28x = 147 

x = 147/28 = 21/4

Answer 2

$\frac{2x}{3} + 5(2x-3) = \frac{3(4x-1)}{2} +11\\\\ \frac{2x+15(2x-3)}{3} = \frac{3(4x-1)+22}{2}\\\\ {2[2x+15(2x-3)]} = {3[3(4x-1)+22]}\\\\ {4x+30(2x-3)} = {9(4x-1)+66}\\\\ 4x + 60x - 90 = 36x - 9 + 66\\\\ 28x = 147\\\\ x = \frac{147}{28}$