Question

qual as coordenadas do ponto médio do segmento AB; A(1 SOBRE 2 ,1) E B(5 SOBRE 2 ,-4)

Answer 1

$<var>Xm= \frac{Xa+Xb}{2}=Xm=\frac{\frac{1}{2}+\frac{5}{2}}{2}\\Xm=\frac{\frac{6}{2}}2=Xm=\frac{3}{2}\\\\Ym=\frac{Ya+Yb}{2}=Ym=\frac{1+(-4)}{2}\\Ym=\frac{1-4}{2}= Ym=\frac{-3}{2}\\\\Pm=(\frac{3}{2},\frac{-3}{2})</var>$