Question

Qual ângulo cujo replemento do suplemento do complemento vale 260º? quero com os cálculos 

Answer 1

$360^{o} -[180^{o}-(90^{o}- \alpha ) ]=260^{o}$

$360^{o} -[180^{o}-90^{o}+ \alpha ]=260^{o}$

$360^{o} -[90^{o}+ \alpha]=260^{o}$

$360^{o} -90^{o}- \alpha =260^{o}$

$270^{o}- \alpha =260^{o}$

$- \alpha =260^{o} -270^{o}$

$- \alpha =-10^{o}$

$\alpha =10^{o}$