Question

Qual a soma dos seis primeiros termos da P.G. (1/81, 1/27, 1/9, ...)?

Answer 1

a1=1/81

q=(1/27)/(1/81)=3

Sn=a1*(1-q^n)/(1-q)

S6=(1/81) * (1- 3⁶)/(1-3)

S6=(1/162) * (729-1) =728/162 =364/81  Letra B