Question

qual a solucao da inequacao 0,2^4x+3 < 0,2^2x+1

Answer 1

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Ola Bellaisa

0.2 = 1/5

(1/5)^(4x+3) < (1/5)^(2x+1) 

5^(-3 - 4x) < 5^(-1 - 2x)

-3 - 4x < -1 - 2x

-2x < 2

2x > -2

x > -1

pronto