Question

qual a resposta disso ?!!

Answer 1

Explicação passo-a-passo:

$\sf lim_{x~\Rightarrow~+\infty}~log_{\frac{1}{2}}~x$

$\sf =lim_{x~\Rightarrow~+\infty}~log_{2^{-1}}~x$

$\sf =lim_{x~\Rightarrow~+\infty}~\dfrac{1}{-1}\cdot log_{2}~x$

$\sf =lim_{x~\Rightarrow~+\infty}~-\underbrace{log_{2}~x}_{+\infty}$

$\sf =\red{-\infty}$