Question

qual a resposta da equaçao de 2° grau 6x²+x-1=0 ?

Answer 1

Basta aplicar Bháskara.

Δ = 1² - 4.6.(-1)
Δ = 1 + 24
Δ = 25 ⇒ √Δ = 5

$x' = \frac{-1-5}{2.6} = \frac{-6}{12} = \frac{-1}{2}$

$x'' = \frac{-1+5}{2.6} = \frac{4}{12} = \frac{1}{3}$

S = {-1/2; 1/3}

Abraço!