Question

Qual a resolução? alguém pode me ajudar?​

Answer 1

$( \frac{4}{9} )^{x + 3} = ( \frac{27}{8} )^{ - 2} \\ (( \frac{2}{3} )^{2} ) ^{x + 3} = (( \frac{3}{2} )^{3} ) ^{ - 2} \\ ( \frac{2}{3} ) ^{2x + 6} = ( \frac{3}{2} ) ^{ - 6} \\ ( \frac{2}{3} ) ^{2x + 6} = ( \frac{2}{3} ) ^{ 6} \\ = > 2x + 6 = 6 \\ 2x = 0 \\ x = 0$