Question

qual a raiz da equação de segundo grau

x²-3x+2=0
​

Answer 1

Resposta: X^2 - 3X + 2 = 0

Por baskara, determina-se disto:

= (-3)^2 - 4.1.2 = 9 - 8 = 1

para as raizes:

X= [-(-3) +/- 1] / 2

X1 = 3 + 1 / 2 = 2

X2 = 3 - 1 / 2 = 1

Solucão Das Raizes

S : {1, 2}

Explicação passo-a-passo: Espero ter ajudado

Answer 2

$\sf \: x {}^{2} - 3x + 2 = 0 \\ \\ \sf \: x = - \frac{ - 3}{2} \frac{ + }{} \sqrt{\Bigg( \frac{ - 3}{2} \Bigg) {}^{2} } - 2 \\ \\ ( - ) + ( - ) = ( +) \\ \\ \sf \: x = \frac{3}{2} \frac{ + }{} \sqrt{\Bigg( \frac{ - 3}{2} \Bigg) {}^{2} } - 2 \\ \\ \sf \: x = \frac{3}{2} \frac{ + }{} \sqrt{ \frac{ - 3 {}^{2} }{2 {}^{2} } } - 2 \\ \\ \sf \: x = \frac{3}{2} \frac{ + }{} \sqrt{ \frac{9}{2 {}^{2} } } - 2 \\ \\ \sf \:x = \frac{3}{2} \frac{ + }{} \sqrt{ \frac{9}{4} } - 2 \\ \\ \sf \: x = \frac{3}{2} \frac{ + }{} \sqrt{ \frac{9}{4} }- \frac{2}{1} \ \\ \ \sf \: m.m.c = 4\\ \\ \sf \: x = \frac{3}{2} \frac{ + }{} \sqrt{ \frac{9 - 2 \times 4}{4} } \\ \\ \sf \: x = \frac{3}{2} \frac{ + }{} \sqrt{ \frac{9 - 8}{4}} \\ \\ \sf \: x = \frac{3}{2} \frac{ +}{} \sqrt{ \frac{1}{4} } \\ \\ \sf \: x = \frac{3}{2} \frac{ + }{} \frac{ \sqrt{1} }{ \sqrt{4} } \\ \\ \sf \: x= \frac{3}{2} \frac{ + }{} \frac{1}{ \sqrt{2 {}^{2} } } \\ \\ \sf \: x = \frac{3}{2} \frac{ + }{} \frac{1}{2} \\ \\ \sf \: x = \frac{3}{2} + \frac{1}{2} \\ \sf \: x = \frac{3}{2} - \frac{1}{2} \\ \\ \sf \: x = \frac{3 + 1}{2} \div 2 \\ \\ \sf \: x = \frac{4}{2} \div 2 \\ \\ \sf \: x = 2 \\ \\ \sf \: x = \frac{3 - 1}{2} \div 2 \\ \\ \sf \: x = \frac{2}{2} \div 2 \\ \\ \sf \: x = 1 \\ \\ \boxed{\sf \: Sol:\Bigg \{x_{1} = 1,x _{2} = 2\Bigg \}}$

Att: Nerd1990