Question

Qual a massa (aproximadamente) presente em 4,35 mol de água?

Answer 1

Resposta:

4,35 mol = 2 . 1 + x

x = 2,35 mL

Answer 2

$m_{H_{2}O}=2.1+16=18g/mol$

$\mathsf{1\,mol\,de\,H_{2}O\rightarrow\,18g}\\\mathsf{4,35\,mols\,de\,H_{2}O\rightarrow\,x}$

$\mathsf{x=4,35\times18}$

$\boxed{\boxed{\mathsf{x=78,3g}}}$