Question

Qual a distribuição eletrônica do 11Na23, 42Mo95, 37Rb85, 26Fe56, (17Cl35)-1, (13Al27)+3, 33 As74, 18 Ar40, (38Sr88)+2, 30Zn65, 24Cr45, (40Zr91)+4 e 31Ga+3

Answer 1

11 Na - 1s2 2s2 2p6 3s1

42 Mo - 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d4

37 Rb - 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1

26 Fe - 1s2 2s2 2p6 3s2 3p6 4s2 3d6

(17 Cl)-1 = 1s2 2s2 2p6 3s2 3p6

(13 Al)+3 = 1s2 2s2 2p6

33 As - 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3

18 Ar - 1s2 2s2 2p6 3s2 3p6

(38 Sr) +2 = 1s1 2s2 2p6 3s2 3p6 4s2 3d10 4p6

30 Zn - 1s2 2s2 2p6 3s2 3p6 4s2 3d10

24 Cr - 1s2 2s2 2p6 3s2 3p6 4s2 3d4

(40 Zr) +4 - 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6

(31 Ga) +3 = 1s2 2s2 2p6 3s2 3p6 4s2 3d8