Question

Qual a distância do ponto (3,2) à reta 2x-6y+1 = 0 ?​

Answer 1

d= A.x + B.y + C / √A²+B²

d= 2.3 + (-6).2+ 1 / √2²+(-6)²

d = 6 - 12 +1 / √40

d = |-5/√40| •(√40/√40)

d= 5√40/40= 5.2√10/40= √10 /4 ✓