Question

qual a derivada de 1/raiz de 2x-8?

Answer 1

Resposta:

$f(x) = \frac{1}{2x-8}$

$f(x) = (2x-8)^{-1}$

$\frac{d}{dx}[(2x-8)^{-1}]$

Use a regra da cadeia, defina u como 2x - 8

$\frac{d}{dx}[u^{-1}] \frac{d}{dx}[2x-8]$

$-u^{-2} \frac{d}{dx} [2x-8]$

$-(2x-8)^{-2} \frac{d}{dx} [2x-8]$

$-[2x-8]^{-2}[\frac{d}{dx}[2x] +\frac{d}{dx} [-8]]$

$-[2x-8]^{-2}.2$

$\frac{-2}{(2x-8)^{2} }$

bons estudos: