Question

qual a base a se tem o longaritmo 16 igual A -2

Answer 1

$\log_a(16) = -2 \\\\\log_a(16) = \log_a(a^{-2}) \\\\a^{-2} = 16 \\\\\dfrac{1}{a^2} = 16 \\\\a^2 = \dfrac{1}{16} \rightarrow a = \sqrt{\dfrac{1}{16}} = \dfrac{1}{4}$