Question

Qual a area de um triangulo equilatero cuja apotema mede √3 ?

Answer 1

$a = \frac{l \sqrt{3} }{6} > \sqrt{3} = \frac{x \sqrt{3} }{6} \\ 6 \sqrt{3} = x \sqrt{3} > x = \frac{ 6\sqrt{3} }{ \sqrt{3} } \\ x = 6$