Question

quais sao os multiplos de 6 compreendidos entre 15 e 500. com a conta pfv

Answer 1

an = a1 + (n - 1) r. entre 15 e 500
18 ...... 498
498 = 18 + (n-1) .6
498= 18 + 6n - 6
498 - 18 + 6 = 6n
486 =6n
n= 486/6. n=81

18,24,30,36,42,48,54,60,66,72,78,84,90,96,102,108,114,120,126,132,138,144,150,156,162,168,174,
180,186,192,198,204,210,216,222,228,234,240,246,252,258,264,270,276,282,288,294,300,
306,
312,318,324,330,336,342,348,354,360,366,
372,378,384,390,396,402,408,414,420,426
,432,438,444,450,456,462,468,474,480,486,
492,498.