Question

quais sao as raizes da equaçao x2+10x+16=0 ?

Answer 1

x² + 10x + 16 = 0

a = 1

b = 10

c = 16

∆ = b² - 4 . a . c

∆ = 10² - 4 . 1 . 16

∆ = 100 - 64

∆ = 36

x = - b ± √∆

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2a

x' = - 10 + 6

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2 . 1

x' = - 4

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2

x' = - 2

x" = - 10 - 6

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2 . 1

x" = - 16

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2

x" = - 8

S = {-2 , -8}

Answer 2

$\large \boxed{ \begin{array}{l} \rm x {}^{2} + 10x + 16 = 0 \\ \\ \rm a = 1 \\ \rm b = 10 \\ \rm c = 16 \\ \\ \rm\Delta = {b}^{2} - 4ac \\ \rm \Delta = 10 {}^{2} - 4.1.16 \\ \rm \Delta = 100 - 64 \\ \rm\Delta = 36 \\ \\ \rm x = \dfrac{ - b \pm \sqrt{\Delta} }{2a} \\ \\ \rm x = \dfrac{ - 10 \pm \sqrt{36} }{2.1} \\ \\ \rm x = \dfrac{ - 10 \pm6}{2} \begin{cases} x_1 = \dfrac{ - 10 + 6}{2} = \dfrac{ - 4}{2} = - 2 \\ \\ \rm x_2 = \dfrac{ - 10 - 6}{2} = \dfrac{ - 16}{2} = - 8 \end{cases} \\ \\ \rm \: S = \{ - 2; - 8\} \end{array}}$