Question

Quais são as raízes da equação 4y²−64m?=0, m>0, no conjunto dos números reais?

Answer 1

$\boxed{\begin{array}{l}\sf 4y^2-64m=0\\\sf4y^2=64m\\\sf y^2=\dfrac{64m}{4}\\\sf y^2=16m\\\sf y=\pm\sqrt{16m}\\\sf y=\pm4\sqrt{m}\end{array}}$