Question

presciso de ajudaaaa

determine os valores reais de x de
log de base x-2 logaritimando(x^2-4x-5).

LOG x-2 (X^2 -4x -5)

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{log_{x - 2}\:(x^2 - 4x - 5)}$

$\mathsf{x^2 - 4x - 5 > 0}$

$\mathsf{(x - 5)(x + 1) > 0}$

$\mathsf{x - 5 > 0 \iff x > 5}$

$\mathsf{x + 1 > 0 \iff x > -1}$

$\mathsf{x - 2 > 0 \iff x > 2}$

$\mathsf{x - 2 \neq 1 \iff x \neq 3}$

$\boxed{\boxed{\mathsf{S = \left\{x \in \mathbb{R}~|~x > 5\right \}}}}$