Question

PREENCHA, PARA CADA FUNÇÃO E CONSTRUA O GRÁFICO NO PLANO CARTESIANO
(preciso de ajuda urgente, vale nota e não quero errar)​

Answer 1

Resposta:

a

Explicação passo-a-passo:

a) f(x) = 2x

x. y. ( x , y )

-2. 2.(-2)= -4 ( -2, -4)

-1. 2.(-1) = -2. (-1, -2)

0. 2. (0) = 0. (0 ,0)

1. 2.(1) = 2. (1, 2 )

2. 2. (2) = 4. (2,4)

b)f(x) = - 2x

x. y. (x,y)

-2. 4. (-2,4)

-1. 2. (-1, 2)

0. 0. (0, 0)

1. -2. (1, -2)

2. -4. (2, -4)

c) f(x) x^2

.

x. y. (x,y)

-2. 4. (-2,4)

-1. 1. (-1, 1)

0. 0. (0, 0)

1. 1. (1 , 1 )

2. 4. ( 2, 4)

obs : Agora é só localizar os pontos(x,y) no plano cartesiano.Espero ter ajudado!!!!

Answer 2

$\large\boxed{\begin{array}{l}\rm a)~f(x)=2x\\\begin{array}{c|c|c|c}\sf x&\sf y&\sf (x,y)\\\sf-2&\sf-4&\sf(-2,-4)\\\sf-1&\sf-2&\sf(-1,-2)\\\sf 0&\sf0&\sf(0,0)\\\sf 1&\sf2&\sf(1,2)\\\sf2&\sf4&\sf(2,4)\end{array}\\\rm o~gr\acute afico~est\acute a~anexo\end{array}}$

$\large\boxed{\begin{array}{l}\rm b)~f(x)=-2x\\\begin{array}{c|c|c|c}\sf x&\sf y&\sf (x,y)\\\sf-2&\sf4&\sf(-2,4)\\\sf-1&\sf2&\sf(-1,2)\\\sf 0&\sf0&\sf(0,0)\\\sf 1&\sf-2&\sf(1,-2)\\\sf2&\sf-4&\sf(2,-4)\end{array}\\\rm o~gr\acute afico~est\acute a~anexo\end{array}}$

$\large\boxed{\begin{array}{l}\rm c)~f(x)=x^2\\\begin{array}{c|c|c|c}\sf x&\sf y&\sf (x,y)\\\sf-2&\sf4&\sf(-2,4)\\\sf-1&\sf1&\sf(-1,1)\\\sf 0&\sf0&\sf(0,0)\\\sf 1&\sf1&\sf(1,1)\\\sf2&\sf4&\sf(2,4)\end{array}\\\rm o~gr\acute afico~est\acute a~anexo\end{array}}$