Preciso urgenteee !!
Resolva os sistemas abaixo:
E: { u+2d+3t=14
{3u-4d+2t=1
{2u+d-t=1
Soluções para a tarefa
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u +2d +3t = 14
u = 14 -2d -3t
42 -6d -9t -4d -2t = 1
-10d -11t = -41
d = -41 -11t/10
28 -4(d) -6t -41 -11t/10 -t = 1
28 +164 +44t/10 -6t -41 -11t/10 -t = 1
26t = -51
t = -51/26
d = -41/10 5610/26
d = -533 + 28050/130
d = 27517/130
u = 14/1 -55034/130 +153/26
u = 1820 -55034 + 765/130
u = -52449/130
u = 14 -2d -3t
42 -6d -9t -4d -2t = 1
-10d -11t = -41
d = -41 -11t/10
28 -4(d) -6t -41 -11t/10 -t = 1
28 +164 +44t/10 -6t -41 -11t/10 -t = 1
26t = -51
t = -51/26
d = -41/10 5610/26
d = -533 + 28050/130
d = 27517/130
u = 14/1 -55034/130 +153/26
u = 1820 -55034 + 765/130
u = -52449/130
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