Question

preciso encontrar as soluções:
{ x = y − 2 2x + y = −1 (R:-1,1)

Poderiam me ajudar?

Answer 1

$\begin{cases}\mathsf{x=y-2}\\\mathsf{2x+y=-1}\end{cases}$

$\mathsf{2(y-2)+y=-1}\\\mathsf{2y-4+y=-1}\\\mathsf{3y=4-1}\\\mathsf{3y=3}\\\mathsf{y=\dfrac{3}{3}}$

$\huge\boxed{\boxed{\boxed{\boxed{\mathsf{y=1}}}}}$

$\mathsf{x=y-2}\\\mathsf{x=1-2}\\\large\boxed{\boxed{\boxed{\boxed{\mathsf{x=-1}}}}}$

$\huge\boxed{\boxed{\boxed{\boxed{\mathsf{s=\{-1,1\}}}}}}$

Answer 2

Resposta:

x = - 1; y = 1

Explicação passo-a-passo:

Sistemas do 1° grau

x = y − 2

2x + y = −1

Método da adição:

x - y = - 2

2x + y = - 1 (+)

----------------

3x = - 3

x = -3/3

x = - 1

x - y = - 2

- 1 - y = - 2

- 1 + 2 = y

1 = y

y = 1

R.:

x = - 1; y = 1